After leading the Seahawks to a stunning, come from behind win in Chicago last Sunday, Seattle quarterback Russell Wilson was named the NFC's Offensive Player of the Week. He's the first Seahawk to win the award since 2005.
The Seattle Seahawks stunned the Chicago Bears last Sunday at Soldier Field, and on Wednesday quarterback Russell Wison was rewarded when he was named the NFC's Offensive Player of the Week.
Wilson was spectacular in the upset win over Chicago, finishing the afternoon with 23 completions in 37 attempts for 293 yards and two touchdowns. He led Seattle on a 12-play, 80-yard drive in overtime, and sealed the victory with a touchdown pass to wide receiver Sidney Rice. With his two touchdown passes, Wilson has now thrown 19 on the season, which is seven shy of Peyton Manning's rookie record set back in 1998.
And in the process of winning the NFC's Offensive Player of the Week, Wilson put Seattle in prime position for one of the NFC's Wild Card berths. The Seahawks currently sit at 7-5 overall and if the playoffs were to start today, Seattle would claim the No. 6 seed in the NFL. They host Arizona on Sunday and are looking to improve to 6-0 at home on the season.
Wilson is the first Seahawk to be named NFC Offensive Player of the Week since Shaun Alexander took home the award during the 2005 season.